| Andi Setiawan (visual_cpp@programmer.net) |
Posted: Mon May 10, 2004 6:01 am Post subject: Others: I am confused with dirac delta and kronecker delta function in sampling theorem |
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I am a graduate student, from electrical engineering. I have no detail mathematical analysis.
====================== Introductory ============================
Let fd(t) be a discritization of f(t).
Many books represent fd(t) as follows
fd(t)=sigma{f(kT)deltaKronecker(t-kT)} where k goes from -inf to +inf.
And then the fourier transform of fd(t) is given by
fd^(w)=sigma{f(kT)exp(-iwkT)} where k goes from -inf to +inf.
===================== My Problem =============================
Why is the fourier transform of deltaKronecker the same as that of deltaDirac ?
In my opinion, fourier transform of deltaDirac(t-c) is exp(-jwc) and the fourier transform of deltaKronecker(t-c) is zero elsewhere.
Maybe I have made misunderstanding, please let me know the correct explanation.
THANK YOU VERY MUCH |
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